Problem with two recordset

2 Message(s) by 2 Author(s) originally posted in php language

From: nervino

Date: Tuesday, September 25, 2007

I am trying to print "selected" when an id of the first recordset is
also present in the second recordset.

I did the code

<software> Instructions for a computer in some programming
	language, often {machine language}.  The word "code" is often
	used to distinguish instructions from {data} (e.g. "The code
	is marked 'read-only'") whereas "{software}" is used in
	contrast with "{hardware}" and may consist of more than just
	code.

	(2000-04-08)

below but it only print out "selected" one time, and I'm
shure there are two id in the second recordset identical to two id of
the first.
What do I mistake?

(I hope my english to be understandable)

Thank youMy code:

$query_cat = "SELECT * FROM cat_documenti ORDER BY categoria ASC";
$result_query_cat=mysql_query($query_cat)
or die('Query failed. ' . mysql_error());

$query_cat_sel = "SELECT id_categoria_doc FROM link_cat_doc WHERE
id_documento =".$id_documento;
$result_query_cat_sel=mysql_query($query_cat_sel)
or die('Query failed. ' . mysql_error());
$dati_recordset = mysql_fetch_array($result_query_news);
$dati_recordset_cat_sel = mysql_fetch_array($result_query_cat_sel);

while ($dati_recordset_cat = mysql_fetch_array($result_query_cat)) {
$id_categoria_doc=$dati_recordset_cat['id_categoria_doc'];
$categoria=$dati_recordset_cat['categoria']; while ($dati_recordset_cat_sel = mysql_fetch_row($result_query_cat_sel)) {

$id = $dati_recordset_cat_sel["id_categoria_doc"];

if (in_array($id_categoria_doc, $dati_recordset_cat_sel)) {
echo " selected=\"selected\"";
}
}
print $categoria;

}

From: C.

Date: Tuesday, September 25, 2007

wrote in message:

I am trying to print "selected" when an id of the first recordset is
also present in the second recordset.
I did the code below but it only print out "selected" one time, and I'm
shure there are two id in the second recordset identical to two id of
the first.
What do I mistake?
(I hope my english to be understandable)
Thank you
My code:
$query_cat = "SELECT * FROM cat_documenti ORDER BY categoria ASC";
$result_query_cat=mysql_query($query_cat)
or die('Query failed. ' . mysql_error());
$query_cat_sel = "SELECT id_categoria_doc FROM link_cat_doc WHERE
id_documento =".$id_documento;
$result_query_cat_sel=mysql_query($query_cat_sel)
or die('Query failed. ' . mysql_error());
$dati_recordset = mysql_fetch_array($result_query_news);
$dati_recordset_cat_sel = mysql_fetch_array($result_query_cat_sel);
while ($dati_recordset_cat = mysql_fetch_array($result_query_cat)) {
$id_categoria_doc=$dati_recordset_cat['id_categoria_doc'];
$categoria=$dati_recordset_cat['categoria'];
while ($dati_recordset_cat_sel = mysql_fetch_row($result_query_cat_sel)) {
$id = $dati_recordset_cat_sel["id_categoria_doc"];
if (in_array($id_categoria_doc, $dati_recordset_cat_sel)) {
echo " selected=\"selected\"";
}
}
print $categoria;
}

FFS use a join

1. <database> {inner join} (common) or {outer join} (less
	common).

	2. <theory> {least upper bound}.

	(1998-11-23)

in one recordset!

C.

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